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	<title>Comments on: Brain Teaser: Making Ends Meet</title>
	<atom:link href="http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/</link>
	<description>Brain Fitness and Cognitive Health news</description>
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		<title>By: paula</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-160924</link>
		<dc:creator>paula</dc:creator>
		<pubDate>Wed, 21 May 2008 18:24:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-160924</guid>
		<description>i don&#039;t think you can say just like that how many people will finish tying the ropes...asumpting that evryone manages to tie the first ends of the ropes and than the other two,we get 2 loops for evry person ..wich means 240 loops...i mean we can only say wich is the maximum number of loops that the 120 persons can create and not how many of them will manage to do what they&#039;re asked</description>
		<content:encoded><![CDATA[<p>i don&#8217;t think you can say just like that how many people will finish tying the ropes&#8230;asumpting that evryone manages to tie the first ends of the ropes and than the other two,we get 2 loops for evry person ..wich means 240 loops&#8230;i mean we can only say wich is the maximum number of loops that the 120 persons can create and not how many of them will manage to do what they&#8217;re asked</p>
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		<title>By: Ali</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-160080</link>
		<dc:creator>Ali</dc:creator>
		<pubDate>Sat, 17 May 2008 12:49:34 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-160080</guid>
		<description>Correction, your solution is the right one since the answer is the same whichever of the 4 ends is selected first.</description>
		<content:encoded><![CDATA[<p>Correction, your solution is the right one since the answer is the same whichever of the 4 ends is selected first.</p>
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		<title>By: Ali</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-160048</link>
		<dc:creator>Ali</dc:creator>
		<pubDate>Sat, 17 May 2008 08:31:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-160048</guid>
		<description>The answer given does not address the problem as initially set out, which was to start by taking a random selection of any two ends at which point you have a 50:50 chance of selecting ends from two different ropes and you end up with an average of 180 loops.  The given answer only works if having already selected one of 4 available ends you are asked to tie that to one of the reamining 3.</description>
		<content:encoded><![CDATA[<p>The answer given does not address the problem as initially set out, which was to start by taking a random selection of any two ends at which point you have a 50:50 chance of selecting ends from two different ropes and you end up with an average of 180 loops.  The given answer only works if having already selected one of 4 available ends you are asked to tie that to one of the reamining 3.</p>
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		<title>By: J</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-159753</link>
		<dc:creator>J</dc:creator>
		<pubDate>Fri, 16 May 2008 00:02:52 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-159753</guid>
		<description>I agree with both B and C&#039;s replies; the question was both unclear and complicated. However, I did like figuring it out and came up with 120 loops, also.</description>
		<content:encoded><![CDATA[<p>I agree with both B and C&#8217;s replies; the question was both unclear and complicated. However, I did like figuring it out and came up with 120 loops, also.</p>
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		<title>By: CB</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-159616</link>
		<dc:creator>CB</dc:creator>
		<pubDate>Thu, 15 May 2008 11:38:37 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-159616</guid>
		<description>I agree completely with C. I don&#039;t see the logic in attempting to complicate a rather simple solution.</description>
		<content:encoded><![CDATA[<p>I agree completely with C. I don&#8217;t see the logic in attempting to complicate a rather simple solution.</p>
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		<title>By: C</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-158891</link>
		<dc:creator>C</dc:creator>
		<pubDate>Mon, 12 May 2008 01:27:08 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-158891</guid>
		<description>B is right. What is a loop for the author?
If I take two ropes and tie them one end to one end, I get a longer rope wit two ends free, Then I tie those two free ends and I get a big loop. Ecah person gets one big loop, which gives a total of 120 loops. What is wrong with this logic versus the formulation of the problem?</description>
		<content:encoded><![CDATA[<p>B is right. What is a loop for the author?<br />
If I take two ropes and tie them one end to one end, I get a longer rope wit two ends free, Then I tie those two free ends and I get a big loop. Ecah person gets one big loop, which gives a total of 120 loops. What is wrong with this logic versus the formulation of the problem?</p>
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		<title>By: Sue</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-155837</link>
		<dc:creator>Sue</dc:creator>
		<pubDate>Thu, 01 May 2008 15:38:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-155837</guid>
		<description>Yeah..yeah
Try this..2 loops for each knot tied and 1 loop that the ties create.</description>
		<content:encoded><![CDATA[<p>Yeah..yeah<br />
Try this..2 loops for each knot tied and 1 loop that the ties create.</p>
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		<title>By: Govardhan</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-155440</link>
		<dc:creator>Govardhan</dc:creator>
		<pubDate>Wed, 30 Apr 2008 08:35:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-155440</guid>
		<description>i dont agree with, what Wes is saying...This question can have multiple answers...</description>
		<content:encoded><![CDATA[<p>i dont agree with, what Wes is saying&#8230;This question can have multiple answers&#8230;</p>
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		<title>By: Paul</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-150392</link>
		<dc:creator>Paul</dc:creator>
		<pubDate>Fri, 11 Apr 2008 07:59:33 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-150392</guid>
		<description>You can not base mathematical logic on a human condition - Assumption. You&#039;re argument is valid, provided your assumption of the people will do, what you expect.</description>
		<content:encoded><![CDATA[<p>You can not base mathematical logic on a human condition &#8211; Assumption. You&#8217;re argument is valid, provided your assumption of the people will do, what you expect.</p>
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		<title>By: zenkat</title>
		<link>http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/comment-page-1/#comment-149480</link>
		<dc:creator>zenkat</dc:creator>
		<pubDate>Fri, 04 Apr 2008 14:05:34 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2008/03/07/brain-teaser-making-ends-meet/#comment-149480</guid>
		<description>Fun little problem, but I have one minor quibble.  Since the initial selection of an open or closed end is random, the answer is a statistical distribution, with 160 loops as the expected mean.

Bonus question: what is the standard deviation of the distribution?</description>
		<content:encoded><![CDATA[<p>Fun little problem, but I have one minor quibble.  Since the initial selection of an open or closed end is random, the answer is a statistical distribution, with 160 loops as the expected mean.</p>
<p>Bonus question: what is the standard deviation of the distribution?</p>
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