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	<title>Comments on: Math Brain Teaser: Concentric Shapes or The Unkindest Cut of All, Part 2 of 2</title>
	<atom:link href="http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/</link>
	<description>Brain Fitness and Cognitive Health news</description>
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		<title>By: Egon_Freeman</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-203285</link>
		<dc:creator>Egon_Freeman</dc:creator>
		<pubDate>Thu, 06 Nov 2008 19:48:36 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-203285</guid>
		<description>I arrived at this conclusion through &quot;grazing both squares in exactly 4 points&quot; - corners of the smaller one, and the &#039;centers&#039; of walls of the bigger one.

Primarily through &quot;spatial reasoning&quot;, rotated the inner square, and arrived at a point stated in the previous puzzle.

10 seconds. Once again, change it to &quot;Easy&quot; (esp. if someone solved, or at least read, the previous puzzle).</description>
		<content:encoded><![CDATA[<p>I arrived at this conclusion through &#8220;grazing both squares in exactly 4 points&#8221; &#8211; corners of the smaller one, and the &#8216;centers&#8217; of walls of the bigger one.</p>
<p>Primarily through &#8220;spatial reasoning&#8221;, rotated the inner square, and arrived at a point stated in the previous puzzle.</p>
<p>10 seconds. Once again, change it to &#8220;Easy&#8221; (esp. if someone solved, or at least read, the previous puzzle).</p>
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		<title>By: easyas123</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-183581</link>
		<dc:creator>easyas123</dc:creator>
		<pubDate>Thu, 04 Sep 2008 09:40:25 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-183581</guid>
		<description>quite easy, i like those kind of problems</description>
		<content:encoded><![CDATA[<p>quite easy, i like those kind of problems</p>
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	<item>
		<title>By: whoop</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-159523</link>
		<dc:creator>whoop</dc:creator>
		<pubDate>Thu, 15 May 2008 01:40:17 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-159523</guid>
		<description>Its easy if you realize that the radius of the circle is both half the diagonal of the smaller square and half the side value of the larger square.</description>
		<content:encoded><![CDATA[<p>Its easy if you realize that the radius of the circle is both half the diagonal of the smaller square and half the side value of the larger square.</p>
]]></content:encoded>
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		<title>By: Peter Cooper</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-159304</link>
		<dc:creator>Peter Cooper</dc:creator>
		<pubDate>Wed, 14 May 2008 02:30:17 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-159304</guid>
		<description>I did it by saying that the outer square&#039;s area is x^2. The internal square&#039;s diagonal length must be x, so its perpendicular length must be the square root of x^2 / 2 (Pythagorus). Squaring that undoes the square root, so you get x^2 compared to x^2 / 2. Factoring down the x^2 to 1, we get 1/0.5.. or 2/1.</description>
		<content:encoded><![CDATA[<p>I did it by saying that the outer square&#8217;s area is x^2. The internal square&#8217;s diagonal length must be x, so its perpendicular length must be the square root of x^2 / 2 (Pythagorus). Squaring that undoes the square root, so you get x^2 compared to x^2 / 2. Factoring down the x^2 to 1, we get 1/0.5.. or 2/1.</p>
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	<item>
		<title>By: &#187; Brain Teasers and Games for adults, with a neuroscience angle: our Top 50 &#160;&#160; &#171; Brain Fitness Revolution at SharpBrains &#160;&#160;&#160;&#160;</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-80777</link>
		<dc:creator>&#187; Brain Teasers and Games for adults, with a neuroscience angle: our Top 50 &#160;&#160; &#171; Brain Fitness Revolution at SharpBrains &#160;&#160;&#160;&#160;</dc:creator>
		<pubDate>Tue, 16 Oct 2007 17:46:33 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-80777</guid>
		<description>[...] 47. For geniuses: Concentric Shapes or The Unkindest Cut of All, Part 2 of 2. [...]</description>
		<content:encoded><![CDATA[<p>[...] 47. For geniuses: Concentric Shapes or The Unkindest Cut of All, Part 2 of 2. [...]</p>
]]></content:encoded>
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		<title>By: T ROY</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-57993</link>
		<dc:creator>T ROY</dc:creator>
		<pubDate>Sun, 15 Jul 2007 06:17:57 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-57993</guid>
		<description>THIS WAS FUN (I GOT THEM ALL OF COURSE EXCEPT THE VEGETABLES.  

FRUIT OF A PINE TREE
(SEEDS ON OUTSIDE)</description>
		<content:encoded><![CDATA[<p>THIS WAS FUN (I GOT THEM ALL OF COURSE EXCEPT THE VEGETABLES.  </p>
<p>FRUIT OF A PINE TREE<br />
(SEEDS ON OUTSIDE)</p>
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		<title>By: Caroline</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-42199</link>
		<dc:creator>Caroline</dc:creator>
		<pubDate>Mon, 14 May 2007 06:30:18 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-42199</guid>
		<description>I think you created a more difficult brain teaser! Nice solution. Now we just need to strengthen those reading attention skills! ;-) (sorry if the picture was misleading - I just like the picture and thought it went with the theme, if not the specifics)</description>
		<content:encoded><![CDATA[<p>I think you created a more difficult brain teaser! Nice solution. Now we just need to strengthen those reading attention skills! <img src='http://www.sharpbrains.com/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' />  (sorry if the picture was misleading &#8211; I just like the picture and thought it went with the theme, if not the specifics)</p>
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		<title>By: stefan</title>
		<link>http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/comment-page-1/#comment-42091</link>
		<dc:creator>stefan</dc:creator>
		<pubDate>Sun, 13 May 2007 16:18:30 +0000</pubDate>
		<guid isPermaLink="false">http://www.sharpbrains.com/blog/2007/05/08/math-brain-teaser-concentric-shapes-or-the-unkindest-cut-of-all-part-2-of-2/#comment-42091</guid>
		<description>I mis-read the instructions to be the opposite: an outer circle, a square inside that and another circle inside the square, and calc the area difference between the *circles*. Perhaps I looked at the picture instead of read the instructions!

Anyway, I solved it with trig (draw a  right triangle with one point in the center, another to a corner of the square and another to a near side of the square). The area of each circle can be derived from the length of the shorter side.

Interestingly, it comes out to the same answer: the outer circle is twice the area of the smaller one!</description>
		<content:encoded><![CDATA[<p>I mis-read the instructions to be the opposite: an outer circle, a square inside that and another circle inside the square, and calc the area difference between the *circles*. Perhaps I looked at the picture instead of read the instructions!</p>
<p>Anyway, I solved it with trig (draw a  right triangle with one point in the center, another to a corner of the square and another to a near side of the square). The area of each circle can be derived from the length of the shorter side.</p>
<p>Interestingly, it comes out to the same answer: the outer circle is twice the area of the smaller one!</p>
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