Comments on: Math Brain Teaser: The Unkindest Cut of All, Part 1 of 2 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/ Brain Fitness and Cognitive Health news Sat, 07 Nov 2009 10:58:08 -0500 http://wordpress.org/?v=2.8.4 hourly 1 By: Bill http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-228117 Bill Fri, 16 Jan 2009 06:38:54 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-228117 You guys are making this too hard. Two isosceles triangles with hypotenuse 25. Each other side is the square root of 12.5. square root of 12.5 squared is 12.5 You guys are making this too hard.

Two isosceles triangles with hypotenuse 25.

Each other side is the square root of 12.5.

square root of 12.5 squared is 12.5

]]> By: alside http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-227668 alside Wed, 14 Jan 2009 18:05:48 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-227668 I believe the purpose for these puzzles is to exercise the portions of the brain that are in use when completing the activity. I believe the purpose for these puzzles is to exercise the portions of the brain that are in use when completing the activity.

]]> By: Egon_Freeman http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-203283 Egon_Freeman Thu, 06 Nov 2008 19:44:40 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-203283 I concur, this puzzle's difficulty setting should be changed to "Easy". I arrived at the result in about 15 seconds, and that's certainly not bragging... I concur, this puzzle’s difficulty setting should be changed to “Easy”. I arrived at the result in about 15 seconds, and that’s certainly not bragging…

]]> By: John http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-194003 John Tue, 07 Oct 2008 22:40:00 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-194003 12.53 where the square root of 2 = 1.41421356 12.53 where the square root of 2 = 1.41421356

]]> By: Sharon http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-185941 Sharon Fri, 12 Sep 2008 02:51:29 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-185941 A^2+b^2=c^2. C = 5, and a =b. 5x5=25=c^2. A^2+b^2=25. a^2 and b^2 therefore both equal 12.5. A^2 is the formula for area, so the area is 12.5 A^2+b^2=c^2. C = 5, and a =b. 5×5=25=c^2. A^2+b^2=25. a^2 and b^2 therefore both equal 12.5. A^2 is the formula for area, so the area is 12.5

]]> By: DJ_Dysfunk http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-162767 DJ_Dysfunk Wed, 28 May 2008 05:11:51 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-162767 Notice two diagonal lines, one for each pair of opposing corners of the square, form four halves of 2 squares. The length of the side of any of these halves is equal to half of 5, or 2.5. The area of a square is one of its sides squared, 2.5^2 = 6.25 * 2 = 12.5, as (again) there are four halves of two squares. Notice two diagonal lines, one for each pair of opposing corners of the square, form four halves of 2 squares. The length of the side of any of these halves is equal to half of 5, or 2.5. The area of a square is one of its sides squared, 2.5^2 = 6.25 * 2 = 12.5, as (again) there are four halves of two squares.

]]> By: Mitch http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-119889 Mitch Mon, 07 Jan 2008 00:53:46 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-119889 12.5 a^2 + b^2 = c^2 You square the length of the diagonal (C). 25 = a^2 + b^2 because its a square both sides are equal. So divide by 2 to get the square of 1 of the sides ie the volume. 12.5
a^2 + b^2 = c^2
You square the length of the diagonal (C).
25 = a^2 + b^2
because its a square both sides are equal. So divide by 2 to get the square of 1 of the sides ie the volume.

]]> By: Hymen http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-111648 Hymen Tue, 18 Dec 2007 03:11:03 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-111648 I concur! I concur!

]]> By: Juan http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-105847 Juan Sun, 02 Dec 2007 18:41:26 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-105847 There is another easy way: The diagonal divides the square in two triangles. Each triangle has an area of bxh/2 b = diagonal h = diagonal / 2 so 5 x 2.5 / 2 = 6.25 6.25 x 2 triangles = 12.5 I think you would have to set the difficulty to Easy. Bye. There is another easy way:

The diagonal divides the square in two triangles. Each triangle has an area of bxh/2
b = diagonal
h = diagonal / 2

so 5 x 2.5 / 2 = 6.25
6.25 x 2 triangles = 12.5

I think you would have to set the difficulty to Easy.

Bye.

]]> By: Omar http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/comment-page-1/#comment-85643 Omar Thu, 01 Nov 2007 22:27:34 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-85643 I feel the solution is too long, easiest thing to do is: you know that the diagonal is sq.rt(2)*x where x is the measurement of the side. since that's true, then swuare the answer nd you're done. so [5/2qrt(2)]^2 = 12.5 I feel the solution is too long, easiest thing to do is:

you know that the diagonal is sq.rt(2)*x where x is the measurement of the side. since that’s true, then swuare the answer nd you’re done. so [5/2qrt(2)]^2 = 12.5

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