Comments on: Math Brain Teaser: The Unkindest Cut of All, Part 1 of 2 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/ Brain Fitness and Cognitive Health news Sun, 12 Oct 2008 05:23:36 +0000 http://wordpress.org/?v=2.0.5 by: John http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-194003 Tue, 07 Oct 2008 22:40:00 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-194003 12.53 where the square root of 2 = 1.41421356 12.53 where the square root of 2 = 1.41421356

]]> by: Sharon http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-185941 Fri, 12 Sep 2008 02:51:29 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-185941 A^2+b^2=c^2. C = 5, and a =b. 5x5=25=c^2. A^2+b^2=25. a^2 and b^2 therefore both equal 12.5. A^2 is the formula for area, so the area is 12.5 A^2+b^2=c^2. C = 5, and a =b. 5×5=25=c^2. A^2+b^2=25. a^2 and b^2 therefore both equal 12.5. A^2 is the formula for area, so the area is 12.5

]]> by: DJ_Dysfunk http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-162767 Wed, 28 May 2008 05:11:51 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-162767 Notice two diagonal lines, one for each pair of opposing corners of the square, form four halves of 2 squares. The length of the side of any of these halves is equal to half of 5, or 2.5. The area of a square is one of its sides squared, 2.5^2 = 6.25 * 2 = 12.5, as (again) there are four halves of two squares. Notice two diagonal lines, one for each pair of opposing corners of the square, form four halves of 2 squares. The length of the side of any of these halves is equal to half of 5, or 2.5. The area of a square is one of its sides squared, 2.5^2 = 6.25 * 2 = 12.5, as (again) there are four halves of two squares.

]]> by: Mitch http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-119889 Mon, 07 Jan 2008 00:53:46 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-119889 12.5 a^2 + b^2 = c^2 You square the length of the diagonal (C). 25 = a^2 + b^2 because its a square both sides are equal. So divide by 2 to get the square of 1 of the sides ie the volume. 12.5
a^2 + b^2 = c^2
You square the length of the diagonal (C).
25 = a^2 + b^2
because its a square both sides are equal. So divide by 2 to get the square of 1 of the sides ie the volume.

]]> by: Hymen http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-111648 Tue, 18 Dec 2007 03:11:03 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-111648 I concur! I concur!

]]> by: Juan http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-105847 Sun, 02 Dec 2007 18:41:26 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-105847 There is another easy way: The diagonal divides the square in two triangles. Each triangle has an area of bxh/2 b = diagonal h = diagonal / 2 so 5 x 2.5 / 2 = 6.25 6.25 x 2 triangles = 12.5 I think you would have to set the difficulty to Easy. Bye. There is another easy way:

The diagonal divides the square in two triangles. Each triangle has an area of bxh/2
b = diagonal
h = diagonal / 2

so 5 x 2.5 / 2 = 6.25
6.25 x 2 triangles = 12.5

I think you would have to set the difficulty to Easy.

Bye.

]]> by: Omar http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-85643 Thu, 01 Nov 2007 22:27:34 +0000 http://www.sharpbrains.com/blog/2007/04/27/math-brain-teaser-the-unkindest-cut-of-all-part-1-of-2/#comment-85643 I feel the solution is too long, easiest thing to do is: you know that the diagonal is sq.rt(2)*x where x is the measurement of the side. since that's true, then swuare the answer nd you're done. so [5/2qrt(2)]^2 = 12.5 I feel the solution is too long, easiest thing to do is:

you know that the diagonal is sq.rt(2)*x where x is the measurement of the side. since that's true, then swuare the answer nd you're done. so [5/2qrt(2)]^2 = 12.5

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